150=-16x^2+96x+10

Solution for 150=-16x^2+96x+10 equation:

150=-16x^2+96x+10

We move all terms to the left:

150-(-16x^2+96x+10)=0

We get rid of parentheses

16x^2-96x-10+150=0

We add all the numbers together, and all the variables

16x^2-96x+140=0

a = 16; b = -96; c = +140;
Δ = b2-4ac
Δ = -962-4·16·140
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-16}{2*16}=\frac{80}{32}
=2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+16}{2*16}=\frac{112}{32}
=3+1/2
$